SOLUTION: The perimeter of a rectangle is 76m. If the width were doubled and the length were increased by 5 m, the perimeter would be 120m. What are the length and width of the original rec

Algebra ->  Equations -> SOLUTION: The perimeter of a rectangle is 76m. If the width were doubled and the length were increased by 5 m, the perimeter would be 120m. What are the length and width of the original rec      Log On


   

Question 403285: The perimeter of a rectangle is 76m. If the width were doubled and the length were increased by 5 m, the perimeter would be 120m. What are the length and width of the original rectangle?
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
If L is the length, W is the width
Perimeter of the rectangle is P=2%28L%2BW%29, so 2%28L%2BW%29=76.
If the width be double (2W) and the length ne increase by 5 m (L+5)? the perimeter will be 2%282W%2B%28L%2B5%29%29=120
Equation system
2%28L%2BW%29=76
2%282W%2B%28L%2B5%29%29=120
.
L%2BW=38
L%2B2W%2B5=60
.
L%2BW=38
L%2B2W=55 From the second equation we subtract the first equation
.
L%2BW=38
W=17
If W=17 from the first equation will have L=38-W=38-17=21
So the length is 21m and the width is 17m