Question 403234: 0.10x+(40-x)0.25=6.70
Joe has $6.70 in quarters and dimes. If there are forty 40 coins in all, how many of each kind are there? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The way I do it is:
Let = number of dimes
Let = number of quarters
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given:
(1)
(2) (in cents)
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Multiply both sides of (1) by , and
subtract (1) from (2)
(2)
(1)
and, from (1),
There are 22 dimes and 18 quarters
check answer:
(2)
(2)
(2)
OK
