SOLUTION: At 2:00pm a runner heads north on a highway, jogging at 10 miles per hour. At 2:30pm a driver heads north on the same highway to pick up the runner. If the car travels at 55 miles

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: At 2:00pm a runner heads north on a highway, jogging at 10 miles per hour. At 2:30pm a driver heads north on the same highway to pick up the runner. If the car travels at 55 miles       Log On


   



Question 403142: At 2:00pm a runner heads north on a highway, jogging at 10 miles per hour. At 2:30pm a driver heads north on the same highway to pick up the runner. If the car travels at 55 miles per hour, how long will it take the driver to catch the runner?
Thanks for any help! :)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
At 2:00pm a runner heads north on a highway, jogging at 10 miles per hour. At 2:30pm a driver heads north on the same highway to pick up the runner.
If the car travels at 55 miles per hour, how long will it take the driver to catch the runner?
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Runner DATA:
rate = 10 mph ; time = x hrs ; distance = rt = 10x miles
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Driver DATA:
rate = 55 mph ; time = x-(1/2) hrs ; distance = rt = 55x-27.5 miles
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Equation:
distance = distance
10x = 55x-27.5
45x = 27.5
x = 27.5/45 = 11/18 hr
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x-(1/2) = (11/18)-(9/18) = 1/9 hr = 6min 40sec (time for the car to catch
the runner)
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Cheers,
Stan H.