SOLUTION: how many different 4 digit PINs can be created using the numbers 2, 3, 0, 6, 7, and 8 with repitition.
i know with repitition it would be 6 x 6 x 6 x 6 = 1296
HOWEVER for a pin n
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-> SOLUTION: how many different 4 digit PINs can be created using the numbers 2, 3, 0, 6, 7, and 8 with repitition.
i know with repitition it would be 6 x 6 x 6 x 6 = 1296
HOWEVER for a pin n
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Question 40314: how many different 4 digit PINs can be created using the numbers 2, 3, 0, 6, 7, and 8 with repitition.
i know with repitition it would be 6 x 6 x 6 x 6 = 1296
HOWEVER for a pin number like 2222 rearranging the numbers is useless because you don't get a new number. This is the same for a number like 2223, or 2233 <- rearranging is pointless.
So, please help me fiigure out how to apply these restrictions with all the numbers Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! You are saying with repition in your question ....
that would be: 6 * 6 * 6 * 6 = 1296
If with limitations of different numbers ....
6 * 5 * 4 * 3 = 360
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