Question 402964: Two cyclists, 72 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Two cyclists, 72 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
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Slower cyclist DATA:
Time = 4 hrs ; rate = x mph ; distance = 4x miles
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Faster cyclist DATA:
Time = 4 hrs: rate = 2x mph ; distance = 8x miles
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Equation:
distance + distance = 72 miles
4x + 8x = 72 miles
8x = 72
x = 9 mph (rate of slower rider)
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2x = 18 mph (rate of faster rider)
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Cheers,
Stan H.
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