SOLUTION: A baseball diamond is laid out so that the bases are 90n feet apart and at right angles as shown at the right. The distance from home plate to the pitcher’s mound is 60 feet 6 inch

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Question 402911: A baseball diamond is laid out so that the bases are 90n feet apart and at right angles as shown at the right. The distance from home plate to the pitcher’s mound is 60 feet 6 inches. Find the distance from the pitcher’s mound to second base. (Hint: The pitcher’s mound is not exactly halfway between home plate and second base.)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A baseball diamond is laid out so that the bases are 90n feet apart and at right angles as shown at the right.
The distance from home plate to the pitcher’s mound is 60 feet 6 inches.
Find the distance from the pitcher’s mound to second base.
:
The distance from home plate to 2nd base is the hypotenuse (h)
h = sqrt%2890%5E2+%2B+90%5E2%29
h = sqrt%288100+%2B+8100%29
h = sqrt%2816200%29
h = 127.279 which is 127 + .279(12) = 127 ft 3.35 inches
therefore:
127' 3.35" - 60' 6" = 66 ft 9.35 inches from pitchers mound to 2nd base