SOLUTION: Simplify and and answer with positive exponents only.
[(-12x^5y^-4)/(3x^-2y)]^-2
x to the power of 5, y to the power of negative 4, 3 to the power of negative 2, y to the pow
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: Simplify and and answer with positive exponents only.
[(-12x^5y^-4)/(3x^-2y)]^-2
x to the power of 5, y to the power of negative 4, 3 to the power of negative 2, y to the pow
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Question 40282: Simplify and and answer with positive exponents only.
[(-12x^5y^-4)/(3x^-2y)]^-2
x to the power of 5, y to the power of negative 4, 3 to the power of negative 2, y to the power of one
everthing in brackets to the power of negative 2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! [(-12x^5y^-4)/(3x^-2y)]^-2
First rewrite the fraction, as follows:
{[(-12x^5)/(y^4)]/[(3y)/x^2]-2}^
=Invert the denominator and multiply
{[(-12x^5)/y^4]}^-2
={-12x^7/3y^5]^-2
=[-4x^7/y^5]^-2
=y^10/16y^14
Cheers,
Stan H.
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