SOLUTION: I need help, please help me find the equation of the line in slope-intercept form and standard form.
Contains point (-3,5) and is perpendicular to 2x+3y=7
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-> SOLUTION: I need help, please help me find the equation of the line in slope-intercept form and standard form.
Contains point (-3,5) and is perpendicular to 2x+3y=7
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Question 402265: I need help, please help me find the equation of the line in slope-intercept form and standard form.
Contains point (-3,5) and is perpendicular to 2x+3y=7
You can put this solution on YOUR website! OK step one: find slope of given function, which means put it in slope intercept form, so y=mx+b, so solve for y.
2x+3y=7 subtract 2x from each side
3y=-2x+7 divide both sides by 3
y=-2x/3+7/3 so slope for this line is m=-2/3
However, our line is perpendicular to this one, so the slope for OUR line is m=3/2 (opposite sign and flip it)
Now we use the point given and this slope and plug it into the point slope formula, which is
y-y1=m(x-x1) where (x1,y1) is the given point so (-3,5) add 5 to each side so this is your slope intercept form.
For standard form just subtract 3x/2 from each side
