SOLUTION: a parking lot has a perimeter of 500 ft. The width of 20 ft. less than the length. Find the dimensions.

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Question 402248: a parking lot has a perimeter of 500 ft. The width of 20 ft. less than the length. Find the dimensions.
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter P=2%2A%28L%2BW%29
L - length
W - width
If width is x ft, then length is (x+20)
Put all in perimeter formula
500=2%2A%28%28x%2B20%29%2Bx%29
500=2%2A%28x%2B20%2Bx%29
500=2%2A%282x%2B20%29
500=4x%2B40
4x=500-40
4x=460
x=460%2F4
x=115
So width is 115 ft, then length is 115+20=135 ft
Answer: 115 ft and 135 ft