Hi
If I m understanding Your question properly: |squaring both sides of the equation
9x + 67 = (x + 5)(x+ 5)
9x + 67 = x^2 + 10 + 25
x^2 + x - 42 = 0
factoring
(x + 7)(x - 6)=0 Note:SUM of the inner product(7x) and the outer product(-6x) =x
(x + 7)= 0 x = -7
(x - 6)=0 x = 6
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