SOLUTION: find the number that is 48 less than twice the opposite of itself

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Question 402197: find the number that is 48 less than twice the opposite of itself
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

Let n represent the number and therefore, -n its opposite. (as n + (-n) = 0)

Question states***

 n - 48 = 2*(-n)

Solving for x

 n - 48 = -2n

   3n = 48

    n = 16

CHECKING our Answer***

  16-48 = -32