You can put this solution on YOUR website! Find the vertex of the graph of the equation y=5+16x-2x^2.
=-2(X^2-2.X*4+4^2)+2*4^2+5
=37-2(X-4)^2
VERTEX IS AT X-4=0....OR...X=4...AT X=4,WE HAVE Y=37..
HENCE VERTEX IS AT (4,37)
Show the algebraic steps used to solve this problem.