SOLUTION: The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third

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Question 402067: The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle.
I came up with 1st 23, 2nd 62 and 3rd 95 is this correct?
Let me know.
Thanks
Lisa Barber
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Made a mistake on the third angle!!

The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle.
I came up with 1st 23, 2nd 62 and 3rd 95 is this correct?
.
Let x = measure of first angle
then
3x = second angle
(x + 3x + 10) = third angle
.
sum of interior angles of a triangle is 180:
x + 3x + x+3x+10 = 180
8x+10 = 180
8x = 170
x = 21.25 deg (first)
.
second:
3x = 3(21.25) = 63.75 deg
.
third:
(x + 3x + 10) = (21.25 + 3(21.25) + 10) = 95 deg