SOLUTION: I need help solving for the variable of "x" in this equation: 2^(x+1)= 192+ 2^(x-1)

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Question 401464: I need help solving for the variable of "x" in this equation:
2^(x+1)= 192+ 2^(x-1)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
I need help solving for the variable of "x" in this equation:
2^(x+1)= 192+ 2^(x-1)
..
2^(x+1)-2^(x-1)=192
factor out 2^(x+1)
2^(x+1)(1-(2^-2))=192 note:(2^(x+1)*2^-2=2^(x-1))
2^(x+1)(1-1/4)=192
2^(x+1)(3/4)=192
2^(x+1)=256
(x+1)log2=log256
x+1=log256/log2=8
ans: x=7