SOLUTION: four times a number added to another number is 36. Three times the first number minus the other number is 20. Can you please tell me the numbers
Question 401359: four times a number added to another number is 36. Three times the first number minus the other number is 20. Can you please tell me the numbers Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website! "Four times a number added to another number is 36. Three times the first number minus the other number is 20. Can you please tell me the numbers."
x = the number
y = other number
4x + y = 36 {four times a number added to another number is 36}
3x - y = 20 {three times the 1st minus other is 20}
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7x = 56 {added the two equations together and eliminated the y}
x = 8 {divided both sides by 7}
The first number is 8.
4x + y = 36 {top equation}
4(8) + y = 36 {substituted 8 in for x}
32 + y = 36 {multiplied 4 by 8}
y = 4 {subtracted 32 from both sides}
The other number is 4.
