SOLUTION: I need to solve by using the elimination method but the fraction is throwing me off and I am not sure how to solve this one. Thank you 0.3x-0.2y=4 0.2x-0.3y=5/23

Algebra ->  Expressions-with-variables -> SOLUTION: I need to solve by using the elimination method but the fraction is throwing me off and I am not sure how to solve this one. Thank you 0.3x-0.2y=4 0.2x-0.3y=5/23      Log On


   



Question 401355: I need to solve by using the elimination method but the fraction is throwing me off and I am not sure how to solve this one. Thank you
0.3x-0.2y=4
0.2x-0.3y=5/23

Answer by dnanos(83) About Me  (Show Source):
You can put this solution on YOUR website!
First multiply by 10 both equations
3x+2y=40
2x-3y=50/23
then multiply the first one by 2 and the second by -3
6x+4y=80
-6x+9y=-150/23
Then add and keep the first one for next steps
3x+2y=40
13y=80-150/23
so
3x+2y=40
13y=(1840-150)/23
so
3x+2y=40
13y=1690/23
We divide the second equation by 13 (because 169=13*13)
3x+2y=40
13y/13=1690/13*23
so
3x+2y=40
y=130/23
then we replace the y value in the first equation.
3x+2*130/23=40
y=130/23
so
3x=40-260/23
y=130/23
so
3x=(920-260)/23
y=130/23
so
3x=660/23
y=130/23
We divide the first equation by 3
x=220/23
y=130/23