SOLUTION: use log12(3)=0.4421 and log12(7)=0.7831 to evaluate log12(48)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: use log12(3)=0.4421 and log12(7)=0.7831 to evaluate log12(48)      Log On


   



Question 401308: use log12(3)=0.4421 and log12(7)=0.7831 to evaluate log12(48)
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
log%2812%2C+%283%29%29+=+0.4421
log%2812%2C+%287%29%29+=+0.7831
We are given these two logarithms. Another base 12 logarithm we can use without having to be told is:
log%2812%2C+%2812%29%29+=+1

The "trick" to this kind of problem is to express the argument of the desired logarithm in terms of products, quotients and/or powers of the arguments of the known logarithms. In this problem the argument of the desired logarithm is 48. The arguments of the known logarithms are 3, 7 and 12. So we want to express 48 as some product(s), quotient(s) and/or power(s) of 3, 7 and/or 12.

First we can find that 48=12*4. But we don't know what log%2812%2C+%284%29%29 is. Can we express a 4 in terms of 3, 7 and/or 12? Answer: 4 = 12/3. So now we have
48+=+12%2A%2812%2F3%29

Now we can find log%2812%2C+%2848%29%29:
log%2812%2C+%2848%29%29+=+log%2812%2C+%2812%2A%2812%2F3%29%29%29
Now we can use a property of logarithms, log%28a%2C+%28p%2Aq%29%29+=+log%28a%2C+%28p%29%29+%2B+log%28a%2C+%28q%29%29, to split the logarithm of a product into the sum of the logarithms of the factors:

Next we can use another property of logarithms, log%28a%2C+%28p%2Fq%29%29+=+log%28a%2C+%28p%29%29+-+log%28a%2C+%28q%29%29, to split the logarithm of a quotient into the difference of the logarithms of the numerator and denominator:

We can now replace each logarithm with its known value:

And simplify: