SOLUTION: Find (if it exists) each function value of f(t)=the square root of t^2+1 and so f(-6)=?

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Question 401298: Find (if it exists) each function value of f(t)=the square root of t^2+1 and so f(-6)=?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
If the function is f%28t%29+=+sqrt%28t%5E2%2B1%29, then f(-6) exists, and is equal to f%28-6%29+=+sqrt%28%28-6%29%5E2%2B1%29+=+sqrt%2837%29.