SOLUTION: find the slope if it exist, of the line containing the points (-6,1/2) and (-3, 1/2)

Algebra ->  Linear-equations -> SOLUTION: find the slope if it exist, of the line containing the points (-6,1/2) and (-3, 1/2)       Log On


   

Question 401253: find the slope if it exist, of the line containing the points (-6,1/2) and (-3, 1/2)
Found 2 solutions by richard1234, josmiceli:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
m+=+DELTA%28y%29%2FDELTA%28x%29+=+%281%2F2-1%2F2%29%2F%28-3-%28-6%29%29+=+0%2F3+=+0, so the slope is 0.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%281%2F2+-+1%2F2%29%2F%28-3+-+%28-6%29%29+=+0%2F3
0%2F3+=+0 zero slope means its a
horizontal line at y+=+1%2F2
so, the slope exits