SOLUTION: Angle A is acute and such that tanA=√6/3.
(a) Show clearly that the exact value of sin A can be written in the form 1/5√k and state the value of k.
(b) Hence, or
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-> SOLUTION: Angle A is acute and such that tanA=√6/3.
(a) Show clearly that the exact value of sin A can be written in the form 1/5√k and state the value of k.
(b) Hence, or
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Question 401144: Angle A is acute and such that tanA=√6/3.
(a) Show clearly that the exact value of sin A can be written in the form 1/5√k and state the value of k.
(b) Hence, or otherwise, show that the value of cos2A is exactly 1/5 Answer by robertb(5830) (Show Source):
