SOLUTION: I need help with this question please. I have done the work but I get stuck when it comes to plugging it back into the equation. 2x+3y= -4 4x+y= -3 I have: -4x+6y= -8 4

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Question 401034: I need help with this question please. I have done the work but I get stuck when it comes to plugging it back into the equation.
2x+3y= -4
4x+y= -3
I have:
-4x+6y= -8
4x+y= -3
The 4's cancel and I am left with 7y= -11
I divided the 7 and have -11 over 7 for y.
I don't understand how to plug it back into the equation.
Thank you.
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
I need help with this question please. I have done the work but I get stuck when it comes to plugging it back into the equation.
2x+3y= -4
4x+y= -3
I have:
-4x+6y= -8 (I think you made an error here when you multiplied the first equation by -2. The result should have been -4x-6y=8

You should have had these two equations to work with,
-4x-6y=8
4x+y=-3
add the equations
-5y=5
y=-1
substitute back into either equation, using the first,
2x+3y= -4
=2x+3*(-1)=-4
=2x-3=-4
=2x=-1
x=-1/2
ans: x=-1/2, y=-1 (This is where the two straight-line equation intersect.
see the graph below: