SOLUTION: Two cyclists, 60 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of t

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Question 400837: Two cyclists, 60 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Found 2 solutions by rfer, josmiceli:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
x+2x=30
3x=30
x=10 mph
2x=20 mph

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
you can think of 1 standing still and the
other moving at the sum of their speeds
60+=+%28r%2B+2r%29%2A2
60+=+6r
r++10 mi/hr
2r+=+20 mi/hr
The speed of the faster cyclist was 20 mi/hr
check answer:
slower cyclist:
d%5B1%5D+=+10%2A2
d%5B1%5D+=+20 mi
faster cyclist:
d%5B2%5D+=+20%2A2
d%5B2%5D+=+40 mi
20+%2B+40+=+60
OK