Question 400766: what is this answer log[6](2x-6)+log[6]x=2
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! what is this answer log[6](2x-6)+log[6]x=2
log[6](2x-6)+log[6]x=2
log6(2x-6)(x)=2 (multiplication rule)
write in exponential form (The base raised to the logarithm of the number is equal to the number)In this case, the base=6, the logarithm of the number=2, and number=(2x-6)(x)
6^2=(2x-6)(x)
36=2x^2-6x
2x^2-6x-36=0
x^2-3x-18=0
(x-6)(x+3)=0
x=6
x=-3
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