SOLUTION: How do I Graph the relation x + |y| = 3. Do I need to solve it first before I can graph it? thanks for your help.

Algebra ->  Rational-functions -> SOLUTION: How do I Graph the relation x + |y| = 3. Do I need to solve it first before I can graph it? thanks for your help.      Log On


   

Question 400576: How do I Graph the relation x + |y| = 3. Do I need to solve it first before I can graph it? thanks for your help.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the relation x + |y| = 3.
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Yes, you should solve for "y":
|y| = 3-x
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y = 3-x when x<= 3
or y = x-3 when x>=3
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Graph both on the same set of axes but restrict each piece of the
graph to the x-interval for which it is defined.
Note: I cannot show you that restricted shape {V} on this site.
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C3-x%2Cx-3%29
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
x+%2B+abs%28y%29+=+3
abs%28y%29+=+3+-+x
Since the left side can never be negative, then the
right side can be zero, but never negative
0+%3C=+3+-+x
Add x to both sides
x+%3C=+3
This makes sense, because if +x%3E3+, then
x+%2B+abs%28y%29+=+3 can never be true
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Also,
x+=+3+-+abs%28y%29
This is the sum of
x+=+3 and
x+=+abs%28y%29
This is not really a function, because there is a (+) and (-) value
of y for each x, so its the sum of 2 functions
x+=+abs%28y%29 and
x+=+abs%28-y%29
Include the restriction x+%3C=+3
I hope this helps, I don't have the tools to graph, but
you should be able to draw it.