Question 400108: The radiator in a car is filled with a solution of 60
per cent antifreeze and 40 per cent water. The manufacturer of
the antifreeze suggests that for summer driving, optimal cooling
of the engine is obtained with only 50 per cent antifreeze. If
the capacity of the raditor is 4.2 liters, how much coolant (in
liters) must be drained and replaced with pure water to reduce
the antifreeze concentration to 50 per cent
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The radiator in a car is filled with a solution of 60
per cent antifreeze and 40 per cent water. The manufacturer of
the antifreeze suggests that for summer driving, optimal cooling
of the engine is obtained with only 50 per cent antifreeze. If
the capacity of the raditor is 4.2 liters, how much coolant (in
liters) must be drained and replaced with pure water to reduce
the antifreeze concentration to 50 per cent
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Equation:
acid - acid + acid = acid
0.60*4.2 - 0.60x + 0x = 0.5*4.2
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Multiply thru by 100 to get:
60*4.2 - 60x + 0 = 50*4.2
-60x = -10*4.2
x = 0.7 liters (amt. of coolant that must be replaced)
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Cheers,
Stan H.
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