Question 400106: Two cyclists, 160 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Two cyclists, 160 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
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Let slower rate be "x" mph.
Then faster rate is "3x" mph.
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Their closing rate is x+3x = 4x mph.
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rate = total distance/total time
rate = 160/4 = 40 mph
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Solve: 4x = 40 mph
x = 10 mph
3x = 30 mph (faster rate)
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Cheers,
Stan H.
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