SOLUTION: The golden ratio. The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the go

Algebra ->  Signed-numbers -> SOLUTION: The golden ratio. The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the go      Log On


   



Question 400032: The golden ratio. The ancient Greeks thought that the
most pleasing shape for a rectangle was one for which the
ratio of the length to the width was approximately 8 to 5,
the golden ratio. If the length of a rectangular painting is
2 ft longer than its width, then for what dimensions would
the length and width have the golden ratio? Use a porportion to solve

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the length L=W+%2B2+ft

L%3AW+=8+%3A+5.........since the length L=W2+%2B2+ft
%28W+%2B2+ft%29+%3A+W+=8+%3A+5
5%28W+%2B2+ft%29++=8+W
5W+%2B10+ft%29+=8+W
+10+ft++=8+W-5W
+10+ft++=+3+W
+10+ft%2F3+=++W
+3.333333+ft+=++W

now find the length:

the length L=W+%2B2+ft
the length L=3.333333+ft+%2B2+ft+=+5.333333+ft

check:
5.333333+%3A+3.333333+=8+%3A+5
1.60000006000000600000060000006+=1.6
1.6=1.6