SOLUTION: A jar of nickels and dimes contains $5.45. there are 8 more dimes than nickels. how many of each are there?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A jar of nickels and dimes contains $5.45. there are 8 more dimes than nickels. how many of each are there?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 400024: A jar of nickels and dimes contains $5.45. there are 8 more dimes than nickels. how many of each are there?
Answer by sofiyac(983) About Me  (Show Source):
You can put this solution on YOUR website!
nickels x
dimes x+8
so value of nickels would be 0.05x and value of dimes would be 0.10(x+8)
then it is true that
0.05x+0.10(x+8)=5.45
0.05x+0.10x+0.80=5.45
0.15x+0.80=5.45
0.15x=4.65
x=31
so there are 31 nickels and 31+8=39 dimes