SOLUTION: The larger of two consecutive intergers is 10 more than twice the smaller. Find the intergers.

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Question 399700: The larger of two consecutive intergers is 10 more than twice the smaller. Find the intergers.
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
if the first integer is x, then the second is (x+1) (because they are two consecutive integers).
The larger of two consecutive integers((x+1)) is 10 more than twice the smaller (x) we can write in this way: x%2F2=%28x%2B1%29-10
x%2F2=x%2B1-10
x%2F2-x=-9
-x%2F2=-9
x=18 the smaller integer
x%2B1=18%2B1=19 the larger integer
Answer 18, 19