SOLUTION: what is the vertical asymptote and horizontal asymptote for f(x)= -x^2 + 2x -3/x^2+x-12

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Question 399689: what is the vertical asymptote and horizontal asymptote for
f(x)= -x^2 + 2x -3/x^2+x-12
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The degree of the numerator is equal to the degree of the denominator, so the horizontal asymptote is y= the ratio of the leading coefficients.

Thia is y = -1/1 , or y =-1 Horizontal Asymptote

Vertical asymptotes can be found by setting the denominator equal to zero.

x^2+x-12=0
(x+4)(x-3)=0
x=-4 or x=3 Vertical Asymptotes

Dr, Robert J. Rapalje, Retired
Seminole State College of Florida