SOLUTION: You have 737 coins that are all either dimes or quarters. If these coins are worth $107, how many of each type of coin do you have?

Algebra ->  Test -> SOLUTION: You have 737 coins that are all either dimes or quarters. If these coins are worth $107, how many of each type of coin do you have?      Log On


   

Question 399413: You have 737 coins that are all either dimes or quarters. If these coins are worth $107, how many of each type of coin do you have?
Found 2 solutions by ewatrrr, nerdybill:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

737 coins

Let x and (737-x) represent the number of quarters and dimes respectively

Question states*** CENTS makes sense

 25x + 10(737-x) = 10700 CENTS

Solving for x 

    15x = 10700 - 7370

      x = 222, the number of quarters.  515 the number of dimes.   (737-222)

CHECKING our Answer***

 25*222 + 10*515 = 10700 or $107.00

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
You have 737 coins that are all either dimes or quarters. If these coins are worth $107, how many of each type of coin do you have?
.
Let q = number of quarters
then
737-q = number of dimes
.
.25q + .10(737-q) = 107
.25q + 73.7-.10q = 107
.15q + 73.7 = 107
.15q = 33.30
q = 222 (number of quarters)
.
number of dimes:
737-q = 737-222 = 515