SOLUTION: i need to graph this equation. i have no idea how to graph letters. please help me. g(x)=(x-3)^-4

Algebra ->  Rational-functions -> SOLUTION: i need to graph this equation. i have no idea how to graph letters. please help me. g(x)=(x-3)^-4      Log On


   

Question 399376: i need to graph this equation. i have no idea how to graph letters. please help me. g(x)=(x-3)^-4
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
g(x)=(x-3)^-4
Write it
y = (x-3)^-4
We can get rid of the neg exponent by using the reciprocal
y = 1%2F%28%28x-3%29%5E4%29
You can see as the value approaches x=3, the value of y will increase tremendously.
We know y will be positive, an even numbered exponent takes care of that
Choose values for x:
x = 1
y = 1%2F%28%281-3%29%5E4%29
y = 1%2F%28%28-2%5E4%29%29
y = 1%2F16
Graph points 1, 1/16
x = 2
y = 1%2F%28%282-3%29%5E4%29
y = 1%2F%28%28-1%5E4%29%29
y = 1
Graph points 2, 1
x = 2.5
y = 1%2F%28%282.5-3%29%5E4%29
y = 1%2F%28%28-.5%5E4%29%29
y = 1%2F.0625
y = 16
Graph points 2.5, 16
Skip x=3, division by 0, the graph will have a hole there
x=3.5
y = 1%2F%28%283.5-3%29%5E4%29
y = 1%2F%28%28.5%5E4%29%29
y = 1%2F.0625
Graph points 3.5, 16
x=4
y = 1%2F%28%284-3%29%5E4%29
y = 1%2F%28%281%5E4%29%29
y = 1%2F1
y = 1
Graph points 4, 1
:
Looks something like this:
+graph%28+300%2C+200%2C+-2%2C+5%2C+-10%2C+30%2C+%28x-3%29%5E-4%29+