SOLUTION: I am sorry, I do not really know what category this should be in. My question is: Two numbers differ by five and have a product of fifty-four. Find Them.

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Question 399348: I am sorry, I do not really know what category this should be in.
My question is: Two numbers differ by five and have a product of fifty-four. Find Them.
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
If one number is x
then other is (x+5)
their product is 54
so: x%2A%28x%2B5%29=54
x%5E2%2B5x-54=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-5+%2B+sqrt%28+5%5E2-4%2A1%2A%28-54%29+%29%29%2F%282%2A1%29+ or x+=+%28-5+-+sqrt%28+5%5E2-4%2A1%2A%28-54%29+%29%29%2F%282%2A1%29+
x+=+%28-5+%2B+sqrt%28+241+%29%29%2F2+ or x+=+%28-5+-sqrt%28+241+%29%29%2F2+
so the first number is x+=+%28-5+%2B+sqrt%28+241+%29%29%2F2+ or x+=+%28-5+-sqrt%28+241+%29%29%2F2+
then the second number is x%2B5+=+%28-5+-sqrt%28+241+%29%29%2F2+ or x+%2B5=+%28-5+%2Bsqrt%28+241+%29%29%2F2+
Answer: (%28-5+%2B+sqrt%28+241+%29%29%2F2 ,%28-5+-sqrt%28+241+%29%29%2F2+); (%28-5+-sqrt%28+241+%29%29%2F2 ,%28-5+%2Bsqrt%28+241+%29%29%2F2+);