SOLUTION: How many gallons of a 10%-salt solution must be mixed with 6 gallons of a 22%-salt solution to obtain a 13%-salt solution

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Question 399000: How many gallons of a 10%-salt solution must be mixed with 6 gallons of a 22%-salt solution to obtain a 13%-salt solution
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
If x is gallons of a 10%-salt solution, then it contains 0.10x gallons of solt
6 gallons of a 22%-salt solution contains 0.22*6=1.32 gallons of solt
if mixed x gallons with 6 gallons, then obtain (x+6) gallons of a 13%-salt solution
(x+6) gallons of a 13%-salt solution contains 0.13*(x+6)
So equation
0.10x%2B1.32=0.13%2A%28x%2B6%29
0.10x%2B1.32=0.13x%2B0.78
0.10x-0.13x=0.78-1.32
-0.03x=-0.54
x=%28-0.54%29%2F%28-0.03%29
x=18gallons of a 10%-salt solution must be mixed with 6 gallons of a 22%-salt solution to obtain a 13%-salt solution