Question 398873: A rectangular field is 4 times as long as it is wide. Let the width be x and the length will therefore be 4x. If the length is decreases by 10 in. and the width is increased by 2 in. the perimeter will be 80 in. Find the dimensions of the original field.
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Ler x= original width
4x= original length
x+2 = new width
4x-10 = new length
2W + 2L = P
2(x+2) + 2(4x-10)=80
2x+4+8x-20=80
10x -16=80
10x = 96
x=9.6 original width
4x= 38.4 = original length
Check:
New width = 9.6 + 2 = 11.6 inches
New lenth = 38.4-10 = 28.4 inches
Perimeter = 2*11.6 + 2*28.4=80 inches
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