SOLUTION: find three consecutive odd integers such that the sum of the first tow odd integers exceed the third by 7.
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Question 398822
:
find three consecutive odd integers such that the sum of the first tow odd integers exceed the third by 7.
Answer by
checkley79(3341)
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Let x, x+2, x+4 be the 3 integers.
x+x+2=x+4+7
2x+2=x+11
2x-x=11-2
x=9 ans. for the first integer.
9+2=11 ans. for the middle integer.
9+4=13 ans. for the largest integer.
Proof:
9+11=13+7
20=20