SOLUTION: What is the equation of the tangent line to f(x)=x^2-2x+3/x-5 at (3,-3)?

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Question 398721: What is the equation of the tangent line to f(x)=x^2-2x+3/x-5 at (3,-3)?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation of the tangent line to f(x)=x^2-2x+3/x-5 at (3,-3)?
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f%28x%29+=+%28x%5E2-2x%2B3%29%2A%28x-5%29%5E-1
The slope of f(x) = f'(x)
f'(x) = %282x-2%29%2F%28x-5%29+-+%28x%5E2-2x%2B3%29%2F%28x-5%29%5E2
f'(3) = -3.5
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m = -3.5 thru (3,-3)
y+3 = -3.5(x-3) = -3.5x + 10.5
7x + 2y = 15