SOLUTION: I have side a= x-2, side b=x and side c=x+2 and it is a right triangle.. I am supposed to solve for x

Algebra ->  Triangles -> SOLUTION: I have side a= x-2, side b=x and side c=x+2 and it is a right triangle.. I am supposed to solve for x      Log On


   

Question 398475: I have side a= x-2, side b=x and side c=x+2 and it is a right triangle.. I am supposed to solve for x
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
(x-2)^2+x^2=(x+2)^2
x^2-4x+4+x^2=x^2+4x+4
x^2-8x=0
x(x-8)=0
x=0 or x=8

Answer: x=8