SOLUTION: 3 children are pythagorean triple at ages 6, 8, and 10. Will they be pythagorean triples again? Show the formula that gave you that answer

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Question 398436: 3 children are pythagorean triple at ages 6, 8, and 10. Will they be pythagorean triples again? Show the formula that gave you that answer
Found 2 solutions by MathLover1, richard1234:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Pythagorean triples are sets of three integers (a, b, and c) which satisfy the equation c%5E2=a%5E2%2Bb%5E2.

There are 16 primitive Pythagorean triples with c ≤ 100:
( 3, 4, 5)
( 5, 12, 13)
( 7, 24, 25)
( 8, 15, 17)
( 9, 40, 41)
(11, 60, 61)
(12, 35, 37)
(13, 84, 85)
(16, 63, 65)
(20, 21, 29)
(28, 45, 53)
(33, 56, 65)
(36, 77, 85)
(39, 80, 89)
(48, 55, 73)
(65, 72, 97)

For example, (3, 4, 5) can be doubled to produce (6, 8, 10), which is a Pythagorean triple

10%5E2+=+6%5E2%2B8%5E2
100+=+36%2B64
100+=+100

and (6, 8, 10) can be doubled to produce (12, 16, 20) which is a Pythagorean triple too
20%5E2+=+12%5E2%2B16%5E2
400+=+144+%2B+256
400+=+400
It is possible to devise a formula for producing Pythagorean triples:
if you choose arbitrary positive integers m%3En, that these equations generate all Pythagorean Triples (x, y, z):
x=m%5E2-n%5E2,

y=2mn,
z=m%5E2%2Bn%5E2
example:
let m=2 and n=1

x=2%5E2-1%5E2=4-1=3,

y=2%2A2%2A1=4,
z=2%5E2%2B1%5E2=4%2B1=5

we got first triple from the list above- (3,4,5)


let m=29 and n=25

x+=+29%5E2-25%5E2+=+841-625+=+216,

y+=+2%2A29%2A25+=+1450,
z+=+29%5E2%2B25%5E2+=+841%2B625+=+1466...we got second triple (216,1450,1466)


check:
1466%5E2+=+216%5E2%2B1450%5E2
2149156+=+46656+%2B+2102500
2149156+=+2149156







Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
You want to find if there is some Pythagorean triple {x, x+2, x+4}, with x+%3C%3E+6. Since x+4 is the longest side,

x%5E2+%2B+%28x%2B2%29%5E2+=+%28x%2B4%29%5E2

x%5E2+%2B+%28x%5E2+%2B+4x+%2B+4%29+=+x%5E2+%2B+8x+%2B+16 Moving everything to one side,

x%5E2+-+4x+-+12+=+0

%28x+-+6%29%28x+%2B+2%29+=+0 --> x = 6 or x = -2. However, x cannot be negative, so the only triple is when x = 6, and they will never be Pythagorean triples again.