SOLUTION: solve (4x+3)^2/3=(16x+44)^1/3

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Question 398302: solve (4x+3)^2/3=(16x+44)^1/3
Answer by mananth(16946) About Me  (Show Source):
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solve (4x+3)^2/3=(16x+44)^1/3
...
take the cube on both sides
(4x+3)^2=(16x+44)
16x^2+24x+9=16x+44
16x^2+24x-16x+9-44=0
16x^2+8x-35=0
Find the roots of the equation by quadratic formula
a= 16 , b =8 , c = -35
b^2-4ac= 2304 .
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-8%2Bsqrt%282304%29%29%2F32
x1= 1.25
x2=%28-8-sqrt%282304%29%29%2F32
x2=-1.75
...
m.ananth@hotmail.ca