Question 398204: I need to figure out the y intercept, x intersept, and symetry of the equation x=y^2-6.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I need to figure out the following of the equation x=y^2-6.
y intercept:
Let x = 0, then y^2-6 = 0; y = +-sqrt(6)
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x intersept:
Let y = 0, then x = -6
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axis of symmetry:
Complete the square to get:
x = (y-0)^2-6
Vertex is (-6,0)
axis of symmetry is y = 0
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Cheers,
Stan H.
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