Question 398166: Two bicyclists, 42 miles apart, begin riding toward each other on a long straight avenue. One cyclist travels 15 miles per hour and the other 20 miles per hour. At the same time, Spot (a greyhound), starting at one cyclist, runs back and forth between the two cyclists as they approach each other. If Spot runs 38 miles per hour and turns around instantly at each cyclist, how far has he run when the cyclists meet?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Two bicyclists, 42 miles apart, begin riding toward each other on a long straight avenue.
One cyclist travels 15 miles per hour and the other 20 miles per hour.
:
Find their travel time (t) when they meet
20t + 15t = 42
t = 42/35
t = 1.2 hrs
:
At the same time, Spot (a greyhound), starting at one cyclist, runs back and
forth between the two cyclists as they approach each other.
If Spot runs 38 miles per hour and turns around instantly at each cyclist,
how far has he run when the cyclists meet?
:
Dog travels 38 mph for 1.2 hrs: 1.2*38 = 45.6 mi
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