SOLUTION: Hi tutors, I need help with the following question: A distinguishing characteristic of entrepreneurs is their willingness to take risks. R.H. Brockhaus (Academy of Manag

Algebra ->  Probability-and-statistics -> SOLUTION: Hi tutors, I need help with the following question: A distinguishing characteristic of entrepreneurs is their willingness to take risks. R.H. Brockhaus (Academy of Manag      Log On


   



Question 397986: Hi tutors,
I need help with the following question:
A distinguishing characteristic of entrepreneurs is
their willingness to take risks. R.H. Brockhaus (Academy of
Management Journal, Sept. 1980) used a choice dilemma questionaire
(CDQ) to measure the risk-taking propensities of successful
entrepreneurs (lower scores associated with a higher tendancy
for risk taking). The CDQ scores are normally distributed
with a mean of 73 and a standard deviation of 9.
If four entrepreneurs are randomly selected, what is the
probability that at least two of them will score more than 74 on
the CDQ?
I tried solving it by the following formula: p(x>=74), then finding the probability using area under the normal curve but I don't know what to do with the information saying at least 2 out of 4 entrepreneurs. I will be really grateful for your help, thanks!

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming that the probability of any ONE entrepreneur getting a score X is normally distributed, the probability of scoring X+%3E=+74 is P%28X+%3E=+74%29=P%28Z+=+%28X-73%29%2F9+%3E=+%2874-73%29%2F9+=+1%2F9%29.
Let
alpha+=+P%28X+%3E=+74%29=+P%28Z+%3E+=+1%2F9%29, and
beta+=+P%28X+%3C+74%29+=+1+-+P%28Z+%3E+=+1%2F9%29.
COMPUTE for these two values alpha and beta.
From here on the binomial distribution takes over.
Thus the probability that at least two of them will score more than 74 on
the CDQ is 4C2%2Aalpha%5E2%2Abeta%5E2+%2B+4C3%2Aalpha%5E3%2Abeta%5E1+%2B+4C4%2Aalpha%5E4.
Compute for this value,and that's it.