SOLUTION: Could someone please help me solve this problem: {{{x^2-y^2+4xy^2+4y^4}}} I tried regrouping the problem like this: {{{(x^2+4xy^2+4y^4)-y^2}}} so I factored it like this: {{{

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Could someone please help me solve this problem: {{{x^2-y^2+4xy^2+4y^4}}} I tried regrouping the problem like this: {{{(x^2+4xy^2+4y^4)-y^2}}} so I factored it like this: {{{      Log On


   

Question 39795: Could someone please help me solve this problem: x%5E2-y%5E2%2B4xy%5E2%2B4y%5E4
I tried regrouping the problem like this: %28x%5E2%2B4xy%5E2%2B4y%5E4%29-y%5E2
so I factored it like this: %28x%2B2y%29%5E2, but what do I do with the -y%5E2?
Any help would be appreciated.
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Looks to me you would just subtract:
%28x%2B2y%29%5E2-y%5E%282%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E2%2B4xy%5E2%2B4y%5E4%29-y%5E2
You have done well.
You now have (x+(2y^2)^2 - y^2
This is the difference of squares: just like a^2-b^2
which factors into (a+b)(a-b)
So, you get
(x+2y^2-y)(x+2y^2+y)
Cheers,
Stan H.