Question 397929: Solve 4 - a-5/a+3 = a^2-1/a+3, and what does a=?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Solve 4 - a-5/a+3 = a^2-1/a+3, and what does a=?
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Multiply thru by (a+3) to get:
4(a+3) - (a-5) = a^2-1
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4a+12 -a+5 = a^2-1
3a+17 = a^2-1
a^2-3a-18 = 0
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Factor:
(a-6)(a+3) = 0
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a = 6 or a = -3.
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But a cannot be -3 as that would
make a+3 be zero in the denominator.
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Only solution:
a = 6
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Cheers,
Stan H.
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