SOLUTION: Maximum numbers that can be formed using all the 4 digits 6 4 8 1 without repetition and which is divisible by 9

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Question 397843: Maximum numbers that can be formed using all the 4 digits 6 4 8
1 without repetition and which is divisible by 9

Found 2 solutions by MathLover1, josmiceli:
Answer by MathLover1(20850) About Me  (Show Source):
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The biggest number that can be formed with just those four digits once each, is 8641 - however - no+number made from those digits can be divided by 9because in order for a number to be exactly divisible by nine - the+sum of the digits must also divide exactly by nine. The sum of the digits 6%2B4%2B8%2B1=+19.


A possible solution is 61%2B8%2F4+=+63 and 7%2A9+=+63


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In order to be divisible by 9, the sum of the
digits must also be divisible by 9
1+%2B+4+%2B+6+%2B+8+=+19
1+%2B+9+=+0
So, no arrangement of these digits is divisible by 9