SOLUTION: What is the equation of a line that is perpendicular to y=-4x-2 and passes through the point (-8,3)?

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Question 397627: What is the equation of a line that is perpendicular to y=-4x-2 and passes through the point (-8,3)?
Found 2 solutions by Fombitz, robertb:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals,
m%5B1%5D%2Am%5B2%5D=-1
-4%2Am%5B2%5D=-1
m%5B2%5D=1%2F4
So then,
y=mx%2Bb
y=-%281%2F4%29x%2Bb
Use the point (-8,3) to solve for b.
3=-%281%2F4%29%28-8%29%2Bb
3=2%2Bb
b=1
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highlight%28y=-%281%2F4%29x%2B1%29

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The line must have the form y = x/4 + c, where c is unknown. Then 3 = -8/4 + c
==> 3 = -2 + c, or c = 5.
Therefore the equation of the line is y = x/4 + 5.