SOLUTION: The Norman window with dimensions as shown is a rectangle topped by a semicircle. If the area of the window is 68.2 square feet, find its height h.
the drawing looks like a squ
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-> SOLUTION: The Norman window with dimensions as shown is a rectangle topped by a semicircle. If the area of the window is 68.2 square feet, find its height h.
the drawing looks like a squ
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Question 397391: The Norman window with dimensions as shown is a rectangle topped by a semicircle. If the area of the window is 68.2 square feet, find its height h.
the drawing looks like a square with "6ft" at the bottom, at the top of the square is a half circle or dome divided like you would a piece of pie. Then next to the picture they have an arrow with "h ft" in the middle of the line going up and down from the top of the dome to the bottom of the square.
Please help me set up an equation & solve problem. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The Norman window with dimensions as shown is a rectangle topped by a semicircle.
If the area of the window is 68.2 square feet, find its height h.
:
some facts about this
The bottom of the rectangle is given as 6', that is also the diameter of the semicircle.
therefore: the radius of the semicircle is 3'
also the height of the rectangle would be (h-3)
:
Given; Semicircle area + rectangle area = 68.2 + [6*(h-3)] = 68.2
Calculate the area of the semi circle
14.137 + 6h - 18 = 68.2
Combine the numbers on the right:
6h = 68.2 - 14.137 + 18
6h = 72.06
h =
h = 12.01 is the height
:
:
Check this by finding the area of the rectangle
height of rectangle 12.01 - 3.01 = 9.01
Rectangle Area: 9.01 * 6 = 54.06
Add the semi-circle area: 14.137
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Total area of the window: 68.197 ~ 68.2
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Did I make this understandable to you?
