Question 397234: given the displacement vectors A=(3i-4j+4k)m and B=(2i+3j-7k)m,find the magnitudes of the following vectors and express each in terms of its rectangular components: a)C=A+B b)D=2A-B
Answer by CharlesG2(834)   (Show Source):
You can put this solution on YOUR website! "given the displacement vectors A=(3i-4j+4k)m and B=(2i+3j-7k)m,find the magnitudes of the following vectors and express each in terms of its rectangular components: a)C=A+B b)D=2A-B"
http://www.tutorvista.com/physics/examples-of-displacement
"In physics the directional distance is called the displacement. The displacement is the distance traversed by the body in the specified direction. In other words, the displacement is defined as the shortest distance between the initial and final positions of the body. Its unit is also metre and it is vector quantity."
displacement has magnitude and direction, so it is a vector quantity
A=(3i-4j+4k)m and B=(2i+3j-7k)m
find a)C=A+B and b)D=2A-B magnitudes and express in terms of their rectangular components
hoping the "m" means meters since that is the unit for a displacement vector
A = 3i - 4j + 4k
B = 2i + 3j - 7k
-B = -2i - 3j + 7k
2A = 6i - 8j + 8k
C = A + B = 5i - j - 3k
D = 2A - B = 4i - 11j + 15k
magnitude of C = |C| = sqrt(5^2 + (-1)^2 + (-3)^2)
|C| = sqrt(25 + 1 + 9)
|C| = sqrt(35)
|D| = sqrt(4^2 + (-11)^2 + 15^2)
|D| = sqrt(16 + 121 + 225)
|D| = sqrt(362)
if I am in error somewhere could someone please let me know?
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