SOLUTION: Beth was required to make a cross-country flight in training for her pilot's license. When she flew from her home airport, a steady 30 miles per hour wind was behind her, and the t

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Question 397197: Beth was required to make a cross-country flight in training for her pilot's license. When she flew from her home airport, a steady 30 miles per hour wind was behind her, and the trip took 5 hours. When she returned against the wind, the flight took 7 hours. Find the plane's speed in still air and the distance traveled each way.
Found 2 solutions by mananth, ewatrrr:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Beth was required to make a cross-country flight in training for her pilot's license. When she flew from her home airport, a steady 30 miles per hour wind was behind her, and the trip took 5 hours. When she returned against the wind, the flight took 7 hours. Find the plane's speed in still air and the distance traveled each way.
plane's speed = x mph
..
with wind speed = x+30
against wind = x-30
...
d=rt. d is same so equate the distance
5(x+30)=7(x-30)
5x+150=7x-210
7x-5x=210+150
2x=360
/2
x= 180 mph speed in still air
..
m.ananth@hotmail.ca

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x represent the speed of the plane

Questions states***   (D = r*t  OR r = D/t

  x + 30 =  D/5

  x - 30 =  D/7

 2x = (12/35) D

  x = (6/35)D

 

  x + 30 =  D /5

(6/35)D + 30 =  D/5

       30 = (1/35)D

      30*35 = D

      1050mi  = D

              x = (6/35)1050 = 180mph



CHECKING our Answer

  150 = 1050/7